A certain radioactive isotope is a​ by-product of some nuclear reactors. Due to an​ explosion, a nuclear reactor experiences a massive leak

Question

A certain radioactive isotope is a​ by-product of some nuclear reactors. Due to an​ explosion, a nuclear reactor experiences a massive leak of this radioactive isotope.​ Fortunately, the isotope has a very short​ half-life of 13 days. Estimate the percentage of the original amount of the isotope released by the explosion that remains 6 days after the explosion.

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Thái Dương 3 years 2021-08-19T04:11:16+00:00 1 Answers 36 views 0

Answers ( )

  1. Latifah
    0
    2021-08-19T04:12:43+00:00
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    Answer:

    \frac{N}{N_o} = 0.726 = 72.6\%

    Step-by-step explanation:

    The following formula can be utilized for this question:

    N = N_o (\frac{1}{2})^{\frac{t}{t_{1/2}} } \\\\\frac{N}{N_o} = (\frac{1}{2})^{\frac{t}{t_{1/2}} } \\\\

    where,

    \frac{N}{N_o} = ratio of the remaining amount to the original amount = ?

    t = tme passed = 6 days

    t_{1/2} = half-life = 13 days

    Therefore,

    \frac{N}{N_o} = (\frac{1}{2} )^{\frac{6\ days}{13\ days} }\\\\

    \frac{N}{N_o} = 0.726 = 72.6\%

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