# A catapult launches a large stone at a speed of 45.0 m/s at an angle of 55.0° with the horizontal. What maximum height does the

Question

A catapult launches a large stone at a speed of 45.0 m/s
at an angle of 55.0° with the horizontal. What maximum
height does the stone reach?
(a) 45.7 m (b) 32.7 m (C) 69.3 m (d) 83.2 m (e) 102 m

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1 year 2021-09-05T02:16:59+00:00 1 Answers 64 views 0

The first step to assess the problem is to do the following:

Explanation:

First thing first is to write the givens:

$$v_0=45.0 \frac{\text{m}}{\text{s}}\\\theta=55.0^\circ\\g=9.81\frac{\text{m}}{\text{s}^2}$$

The gravitational constant is given typically as 9.81 or 10.

The following step would be to pick out which equation which will solve for the maximum height is going to use which is the following:

$$h=\frac{v^2\sin^2(\theta)}{2g}$$

The rest is plug and chug make sure your calculator is in degrees:

$$h=\frac{(45.0)^2(\sin^2(55.0^\circ)}{2*9.81}\\h=69.255\approx69.3 \ \text{meters}$$