A carousel has a diameter of 6.0-m and completes one rotation every 1.7s. Find the centripetal acceleration of the traveler in m / s2.

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Physics Cherry 6 months 2021-08-31T10:39:03+00:00 2021-08-31T10:39:03+00:00 1 Answers 0 views 0

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MichaelMet · Answer 1 · 2021-08-31T10:40:23+00:00

MichaelMet

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2021-08-31T10:40:23+00:00 August 31, 2021 at 10:40 am

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Answer:

The centripetal acceleration of the traveler is $40.98\ m/s^2$

Explanation:

It is given that, A carousel has a diameter of 6.0-m and completes one rotation every 1.7 s.

We need to find the centripetal acceleration of the traveler. It is given by the formula as follows :

$a=\dfrac{v^2}{r}$

r is radius of carousel

$v=\dfrac{2\pi r}{T}$

So,

$a=\dfrac{4\pi ^2r}{T^2}$

Plugging all the values we get :

$a=\dfrac{4\pi ^2\times 3}{(1.7)^2}\\\\a=40.98\ m/s^2$

So, the centripetal acceleration of the traveler is $40.98\ m/s^2$ .