A carousel has a diameter of 6.0-m and completes one rotation every 1.7s. Find the centripetal acceleration of the traveler in m / s2.

Question

A carousel has a diameter of 6.0-m and completes one rotation every 1.7s. Find the centripetal acceleration of the traveler in m / s2.

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Cherry 6 months 2021-08-31T10:39:03+00:00 1 Answers 0 views 0

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    2021-08-31T10:40:23+00:00

    Answer:

    The centripetal acceleration of the traveler is 40.98\ m/s^2

    Explanation:

    It is given that, A carousel has a diameter of 6.0-m and completes one rotation every 1.7 s.

    We need to find the centripetal acceleration of the traveler. It is given by the formula as follows :

    a=\dfrac{v^2}{r}

    r is radius of carousel

    v=\dfrac{2\pi r}{T}

    So,

    a=\dfrac{4\pi ^2r}{T^2}

    Plugging all the values we get :

    a=\dfrac{4\pi ^2\times 3}{(1.7)^2}\\\\a=40.98\ m/s^2

    So, the centripetal acceleration of the traveler is 40.98\ m/s^2.

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