A car moving at 36 m/s passes a stationary police car whose siren has a frequency of 500 Hz. What is the change in the frequency (in Hz) hea

Question

A car moving at 36 m/s passes a stationary police car whose siren has a frequency of 500 Hz. What is the change in the frequency (in Hz) heard by an observer in the moving car as he passes the police car? (The speed of sound in air is 343 m/s.)

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Thu Giang 5 years 2021-08-10T13:59:28+00:00 1 Answers 93 views 0

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  1. thanhha
    0
    2021-08-10T14:00:30+00:00
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    Answer:

    Change in the frequency (in Hz) = 104.96 Hz

    Explanation:

    Given:

    Speed of sound in air (v) = 343 m/s

    Speed of car (v1) 36 m/s

    Frequency(f) = 500 Hz

    Find:

    Change in the frequency (in Hz)

    Computation:

    Frequency hear by the observer(before)(f1) = [f(v+v1)] / v

    Frequency hear by the observer(f1) = [500(343+36)] / 343

    Frequency hear by the observer(f1) = 552.48 Hz

    Frequency hear by the observer(after)(f2) = [f(v-v1)] / v

    Frequency hear by the observer(f2) = [500(343-36)] / 343

    Frequency hear by the observer(f2) = 447.52 Hz

    Change in the frequency (in Hz) = f1 – f2

    Change in the frequency (in Hz) = 552.48 Hz – 447.52 Hz

    Change in the frequency (in Hz) = 104.96 Hz

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