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A car is travelling at 27m/s and decelerates at a=5m/s2 for a distance of 10m. Calculate its final velocity. (Hint does deceleration imply t
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Answers ( )
If deceleration = 5 m/s²
then acceleration = -5 m/s²
According to third law of motion,
= v² = 2as + u²
= v² = 2×-5×10 + 27²
= v² = -100 + 729
= v =√ 629
= 25.08 m/s