A car is moving at 10 m/s on a horizontal road with friction on a dry day. The car can travel around a traffic circle with a minimum radius

Question

A car is moving at 10 m/s on a horizontal road with friction on a dry day. The car can travel around a traffic circle with a minimum radius of 4.8 meters. It rains and the car around a traffic circle with a minimum radius of 11.8 meters. What is the percentage of the coefficient of static friction on the rainy day compared to the dry day

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Khánh Gia 4 years 2021-07-20T17:26:41+00:00 1 Answers 7 views 0

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  1. thuthao
    0
    2021-07-20T17:28:22+00:00
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    Answer:

    \mu_w=86\%

    Explanation:

    From the question we are told that:

    Velocity on Dry road V_d=10m/s

    Radius Dry r_d=4.8

    Radius wet r_w=11.8

    Generally the equation for coefficient of static friction on the dry day is mathematically given by

    \mu mg=\frac{mv^2}{r_d}

    \mu g=\frac{v^2}{r_d}

    \mu_d 9.8=\frac{10^2}{4.8}

    \mu_d=2.125

    Generally the equation for the relationship between Radius & coefficient of static friction is mathematically given by

    \frac{\mu_d}{\mu_w}=\frac{r_d}{r_w}

    \frac{\mu_w}{2.125}=\frac{4.8}{11.8}

    \mu_w=0.86

    Therefore

    \mu_w=86\%

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