A car accelerates uniformly from rest to a speed of 18 m/s in 12 seconds. Find the acceleration of the car over this period.

Question

A car accelerates uniformly from rest to a speed of 18 m/s in 12 seconds. Find the acceleration of the car over this period.

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Nem 4 years 2021-07-30T20:20:08+00:00 1 Answers 52 views 0

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    2021-07-30T20:21:57+00:00

    The correct answer is 1.5 m/ s^{2}

    Explanation:

    In general terms, the acceleration refers to how velocity changes or increases. This is measured in meters per second squared (m/s^{2}) or similar units such as kilometers per hour squared (km/h^{2}). Moreover, to calculate acceleration it is necessary to subtract the initial velocity from the final velocity and then divide this into the time. The formula and operation are shown below:

    a (acceleration) = \frac{v (final velocity) - u (initial velocity)}{t (time)}

    a= \frac{18 m/s - 0 m/s}{12 s}    (Initial velocity is 0 m/s because the car was at rest)

    a = \frac{18 m/s}{ 12 s}

    a = 1.5 m/s^{2}

    According to this, the acceleration of the car was 1.5 m/s^{2}

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