A candle is placed 50 cm from a diverging lens with a focal length of 28. What is the image distance in cm.

Question

A candle is placed 50 cm from a diverging lens with a focal length of 28. What is the image distance in cm.

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Nho 5 years 2021-08-19T23:42:24+00:00 1 Answers 16 views 0

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  1. Dau
    0
    2021-08-19T23:44:21+00:00
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    Answer:

    v = -17.94 cm

    Explanation:

    Given that,

    The candle is placed at a distance of 50 cm, u = -50 cm

    The focal length of the diverging lens, f = -28 cm (negative in case of a concave lens)

    We need to find the image distance. We know that the lens formula is as follows:

    \dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(-28)}+\dfrac{1}{(-50)}\\\\v=-17.94\ cm

    So, the image distance is equal to 17.94 cm.

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