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A boy throws a ball vertically up. It returns to the ground after 5 seconds. Find (a) the maximum height reached by the ball.
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Answers ( )
Answer:
31.25 m
25m/sec
Explanation:
Given :-
Time = 5sec
V = 0 (in going up)
U = 0 (in comming down)
Find :-
H and U by which it is thrown up
Since the total time is 5 sec ,therefore half time will be taken to go up and another half will be taken to go down .
We know that ,
V = U + gt
0 = U – 10*2.5
U = 25 m/sec
Also,
V² = U² +2gs
0 = 625 – 20s
s = 625/20 = 31.25 m