A bowl containing 70 grams of water, is heated from 10 °C to 90 °C. The specific heat of water is 4.184 J/gºC. How much heat energy is

Question

A bowl containing 70 grams of water, is heated from 10 °C to 90 °C. The specific heat of
water is 4.184 J/gºC. How much heat energy is required to heat the water?

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Mít Mít 3 years 2021-08-14T19:22:20+00:00 1 Answers 6 views 0

Answers ( )

    0
    2021-08-14T19:24:10+00:00

    Answer:

    23430.4 J.

    Explanation:

    From the question given above, the following data were obtained:

    Mass (M) = 70 g

    Initial temperature (T₁) = 10 °C

    Final temperature (T₂) = 90 °C

    Specific heat capacity (C) = 4.184 J/gºC

    Heat (Q) required =?

    Next, we shall determine the change in the temperature of water. This can be obtained as follow:

    Initial temperature (T₁) = 10 °C

    Final temperature (T₂) = 90 °C

    Change in temperature (ΔT) =?

    ΔT = T₂ – T₁

    ΔT = 90 – 10

    ΔT = 80 °C

    Finally, we shall determine the heat energy required to heat up the water. This can be obtained as follow:

    Mass (M) = 70 g

    Change in temperature (ΔT) = 80 °C

    Specific heat capacity (C) = 4.184 J/gºC

    Heat (Q) required =?

    Q = MCΔT

    Q = 70 × 4.184 × 80

    Q = 23430.4 J

    Therefore, 23430.4 J of heat energy is required to heat up the water.

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