A body is projected from aa point such that the horizontal and vertical components of its velocity are 640ms^-^1 and [tex]480 ms^

Question

A body is projected from aa point such that the horizontal and vertical components of its velocity are 640ms^-^1 and 480 ms^-^1 respectively . (Take g = 10ms^-^1 )
i. Calculate the greatest height attained above the point of projection
A.600m B.1215 m C.1521 m D. 11520m E. 20480m

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bonexptip 5 years 2021-07-23T23:16:10+00:00 1 Answers 59 views 0

Answers ( )

  1. Xavia
    0
    2021-07-23T23:18:05+00:00
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    D. 11520m

    Answer:

    Solution given:

    initial velocity[u]=480m/s

    g=10m/s²

    maximum height=?

    now

    we have

    maximum height=\frac{u²sin²\theta}{2g}

    where

    \theta=90°

    =\frac{480²*sin90}{2*10}=11520m

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