A body accelerate uniformly from rest at 0.2m/s for one-fifth of a minute. Calculate the distance covered by the body.​

Question

A body accelerate uniformly from rest at 0.2m/s for one-fifth of a minute. Calculate the distance covered by the body.​

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Verity 3 years 2021-08-19T07:58:05+00:00 1 Answers 3 views 0

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  1. RuslanHeatt
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    2021-08-19T07:59:37+00:00
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    Answer:

    14.4 m

    The distance covered by the body is 14.4 m.

    Solution,

    Initial velocity(u)= 0 m/s( according to Question, the body starts from rest.that‘s why initial velocity(u) becomes zero.

    Acceleration (a)= 0.2 m/s

    Time (t):

    \frac{1}{5} minute = \frac{1}{5 } \times 60 \: seconds

    = 12 \: seconds

    Now,

    Applying third equations of motion:

    s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 \times 12 + \frac{1}{2} \times 0.2 \times {(12)}^{2} \\s = 0 + 14.4 \\ s = 14.4 \: metre

    Thus, the distance covered by the body is 14.4 metre.

    Further more information:

    Application of equation of motion in different situation:

    • When a certain object comes in motion from rest, in the case, initial velocity(u)= 0 m/s
    • When a moving object comes in rest,in the case, final velocity(v)= 0 m/s
    • If the object is moving with uniform velocity, in the case, (u=v)
    • If any object is thrown vertically upward, in the case, acceleration (a)= -g
    • When an object is falling from certain height, in the case, u= 0 m/s
    • When an object is thrown vertically upwards in the case, final velocity at maximum height becomes 0.

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