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## A body accelerate uniformly from rest at 0.2m/s for one-fifth of a minute. Calculate the distance covered by the body.

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## Answers ( )

Answer:14.4mThedistancecoveredbythebodyis14.4m.Solution,Initialvelocity(u)=0m/s(accordingtoQuestion,thebodystartsfromrest.that‘swhyinitialvelocity(u)becomeszero.Acceleration(a)=0.2m/sTime(t):Now,Applyingthirdequationsofmotion:Thus,thedistancecoveredbythebodyis14.4metre.Furthermoreinformation:Applicationofequationofmotionindifferentsituation:Whenacertainobjectcomesinmotionfromrest,inthecase,initialvelocity(u)=0m/sWhenamovingobjectcomesinrest,inthecase,finalvelocity(v)=0m/sIftheobjectismovingwithuniformvelocity,inthecase,(u=v)Ifanyobjectisthrownverticallyupward,inthecase,acceleration(a)=-gWhenanobjectisfallingfromcertainheight,inthecase,u=0m/sWhenanobjectisthrownverticallyupwardsinthecase,finalvelocityatmaximumheightbecomes0.