A block whose weight is 45.8 N rests on a horizontal table. A horizontal force of 36.6 N is applied to the block. The coefficients of static

Question

A block whose weight is 45.8 N rests on a horizontal table. A horizontal force of 36.6 N is applied to the block. The coefficients of static and kinetic friction are 0.697 and 0.371, respectively. Will the block move under the influence of the force, and, if so, what will be the block’s acceleration? If the block does not move, give 0 m/s2 as the acceleration?

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Tài Đức 4 years 2021-07-17T10:43:45+00:00 1 Answers 17 views 0

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  1. dangkhoa
    0
    2021-07-17T10:45:34+00:00
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    Answer:

    Yes it will move and a= 4.19m/s^2

    Explanation:

    In order for the box to move it needs to overcome the maximum static friction force

    Max Static Friction = μFn(normal force)

    plug in givens

    Max Static friction = 31.9226

    Since 36.6>31.9226, the box will move

    Mass= Wieght/g which is 45.8/9.8= 4.67kg

    Fnet = Fapp-Fk

    = 36.6-16.9918

    =19.6082

    =ma

    Solve for a=4.19m/s^2

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