A block of mass 15 kg is sliding along the ice at a constant speed of 4.0 m/s. Just ahead of it is a block of mass 23 kg sliding in the same

Question

A block of mass 15 kg is sliding along the ice at a constant speed of 4.0 m/s. Just ahead of it is a block of mass 23 kg sliding in the same direction at a constant speed of 3.6 m/s. When the two blocks collide, the 23 kg block travels at a new speed of 5.2 m/s. What is the new speed of the 15 kg block?

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Tryphena 4 years 2021-08-29T03:51:30+00:00 1 Answers 19 views 0

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  1. thnahdat
    0
    2021-08-29T03:53:29+00:00
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    Answer:

    1.55 m/s

    Explanation:

    Following the law of conservation of linear momentum, momentum is conserved hence the sum of initial and final momentum are the same

    p=mv where p is momentum, m is the mass of object and v is the velocity of the same object.

    m_1v_1+m_2v_2= m_1V_3+ m_2V_4 where m and v represent mass and velocity respectively, subscripts 1 and 2 represent initial speed of 15 Kg block and 23 kg block respectively, subscripts 3 and 4 represent final speed of 15 Kg block and 23 kg block respectively.

    By substitution

    15*4+(23*3.6)=23*5.2+15V_3\\15V_3=23.2\\V_3=1.546666667\approx 1.55 m/s

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