A beam of light strikes a sheet of glass at an angle of 56.6° with the normal in air. You observe that red light makes an angle of 38.4° wit

Question

A beam of light strikes a sheet of glass at an angle of 56.6° with the normal in air. You observe that red light makes an angle of 38.4° with the normal in the glass, while violet light makes a 36.4° degree angle.
1.What are the indexes of refraction of this glass for these colors of light?

2.What are the speeds of red and violet light in the glass?

in progress 0
Nem 3 years 2021-07-20T11:05:09+00:00 1 Answers 164 views 0

Answers ( )

  1. Eirian
    0
    2021-07-20T11:06:25+00:00
    Reply

    Answer:

    (a). Index of refraction are n_{red} = 1.344 & n_{violet} = 1.406

    (b). The velocity of red light in the glass v_{red} = 2.23 ×10^{8} \ \frac{m}{s}

    The velocity of violet light in the glass v_{violet} =2.13 ×10^{8} \ \frac{m}{s}

    Explanation:

    We know that

    Law of reflection is

    n_1 \sin\theta_{1} = n_2 \sin\theta_{2}

    Here

    \theta_1 = angle of incidence

    \theta_2 = angle of refraction

    (a). For red light

    1 × \sin 56.6 = n_{red} × \sin 38.4

    n_{red} = 1.344

    For violet light

    1 × \sin 56.6 = n_{violet} × \sin 36.4

    n_{violet} = 1.406

    (b). Index of refraction is given by

    n = \frac{c}{v}

    n_{red} = 1.344

    v_{red} = \frac{c}{n_{red} }

    v_{red} = \frac{3(10^{8} )}{1.344}

    v_{red} = 2.23 ×10^{8} \ \frac{m}{s}

    This is the velocity of red light in the glass.

    The velocity of violet light in the glass is given by

    v_{violet} = \frac{3(10^{8} )}{1.406}

    v_{violet} =2.13 ×10^{8} \ \frac{m}{s}

    This is the velocity of violet light in the glass.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )