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## A banked circular highway curve is designed for traffic moving at 57 km/h. The radius of the curve is 216 m. Traffic is moving along the hig

Question

A banked circular highway curve is designed for traffic moving at 57 km/h. The radius of the curve is 216 m. Traffic is moving along the highway at 43 km/h on a rainy day. What is the minimum coefficient of friction between tires and road that will allow cars to take the turn without sliding off the road

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Physics
3 years
2021-09-05T12:29:44+00:00
2021-09-05T12:29:44+00:00 1 Answers
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## Answers ( )

Answer:The minimum coefficient of friction must be

0.067Explanation:In order to allow the cars to take the turn without sliding off the road, the Centripetal Force must be equal to the frictional force between the tires of the car and road.

Centripetal Force = Frictional Forcebut centripetal force = mv²/r

and friction force = μR

mv²/r = μRwhere,

m = mass of car

v = speed of car = 43 km/h = 11.94 m/s

r = radius of circle = 216 m

μ = coefficient of friction = ?

R = Normal Reaction = Weight of Car = mg

Therefore,

mv²/r = μmgμ = v²/grμ = (11.94 m/s)²/(9.8 m/s²)(216 m)μ = 0.067