A 8.0-cm long solenoid has 2000 turns of wire and carries a current of 5.0-A. Calculate the strength of the magnetic field at the center of

Question

A 8.0-cm long solenoid has 2000 turns of wire and carries a current of 5.0-A. Calculate the strength of the magnetic field at the center of the solenoid in teslas.

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Hải Đăng 5 years 2021-08-07T14:24:16+00:00 1 Answers 14 views 0

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    2021-08-07T14:25:48+00:00

    Answer:

    B = 0.157 T

    Explanation:

    Given that,

    Length of the solenoid, l = 8 cm = 0.08 m

    Number of turns in the wire, N = 2000

    Current, I = 5 A

    We need to find the strength of the magnetic field at the center of the solenoid. It is given by the formula as follows :

    N=\mu_o nI, N is number of turns per unit length of solenoid.

    So,

    B=4\pi \times 10^{-7}\times \dfrac{2000}{0.08}\times 5\\\\=0.157\ T

    So, the magnetic field at the center of the solenoid is 0.157 T.

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