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A 7600 kg satellite is in a circular orbit around Earth at a height of 2300 km above Earth’s surface. What is this satellite’s speed
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Answers ( )
Answer:
6779.7m/s
Explanation:
Using
GMm/(Re +h)² = mv²/ (Re+h)
So making v subject we have
V= √GM/Re+h
So
V = √ 6.67*10^-11 x 5.97*10^24/(6371+2300)*10^3
V= 6779.7m/s
Note h = height of satellite
Re= radius of the earth
M = mass of the earth