A 75-g mass sits 75 cm from the center of a rotating platform undergoing a uniform angular acceleration of 0.125 rad/s^2. The coefficient of

Question

A 75-g mass sits 75 cm from the center of a rotating platform undergoing a uniform angular acceleration of 0.125 rad/s^2. The coefficient of static friction between the mass and the platform is 0.250.
What is the speed of the mass when it slides off?
a. 0.889 m/s
b. 1.36 m/s
c. 1.44 m/s
d. 1.58 m/s
e. It will never slide off.

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Diễm Thu 3 years 2021-07-22T13:12:09+00:00 1 Answers 18 views 0

Answers ( )

  1. minhkhang
    0
    2021-07-22T13:13:25+00:00
    Reply

    Answer:

    velocity of mass when it slides of will be 1.36 m/sec

    So option (b) will be correct option.

    Explanation:

    We have given mass of the slits m = 75 gram = 0.075 kg

    Radius r = 75 cm = 0.75 m

    Coefficient of kinetic friction \mu =0.250

    Acceleration due to gravity g=9.8m/sec^2

    When the mass slides of

    \frac{mv^2}{r}=\mu mg

    v=\sqrt{\mu rg}=\sqrt{0.250\times 0.75\times 9.8}=1.36m/sec

    So velocity of mass when it slides of will be 1.36 m/sec

    So option (b) will be correct option.

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