A 66-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.9

Question

A 66-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.90 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.6 s, and then comes to rest. What does the spring scale register in each of the following time intervals?

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Ladonna 3 years 2021-08-21T04:41:23+00:00 1 Answers 8 views 0

Answers ( )

  1. phucdien
    0
    2021-08-21T04:42:36+00:00
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    Answer:735.46N, 626.34N

    Explanation: when an elevator ascend, it means it moving against gravity

    F= m(a+g)

    M=66kg

    a=v/t

    g=9.81m/s^2

    For the first a= 1.2/0.9

    a=1.2/0.9

    a=1.33m/s2

    F=66(1.33+9.81)

    F=66(11.143)

    F=735.46N

    F=m(a+g)

    a=v/t

    a=-1.6/5

    a=-0.32m/s2

    F=66(-0.32+9.8)

    F=66(9.49)

    F=626.34N

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