A 6000 kg lorry is reversing into a parking space at a speed of 0.5 m/s but collides with a car. The crumple zone of the car stops the lorry

Question

A 6000 kg lorry is reversing into a parking space at a speed of 0.5 m/s but collides with a car. The crumple zone of the car stops the lorry in 1.5 seconds. What was the impact force?

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Thiên Thanh 1 month 2021-08-12T07:54:57+00:00 1 Answers 2 views 0

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    2021-08-12T07:56:00+00:00

    Answer:

    -200 N

    Explanation:

    Force: This can be defined as the product of mass and acceleration The S.I unit is N

    The expression for force is given as

    F = m(v-u)/t………………. Equation 1

    Where F = Impact force, m = mass of the lorry , v = Final velocity of the lorry , u = initial velocity of the lorry, t = time

    Given: m = 6000 kg, v = 0 m/s (the lorry was stopped), u = 0.5 m/s, t = 1.5 s

    Substitute into equation 1

    F = 6000(0-0.5)/1.5

    F = -300/1.5

    F = -200 N.

    Note: The negative sign shows that the impact force act in opposite direction to the initial motion of the lorry

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