A 60 turn, 10.0 cm diameter coil rotates at an angular velocity of 8.00 rad/s in a 1.20 T field, starting with the normal of the plane of th

Question

A 60 turn, 10.0 cm diameter coil rotates at an angular velocity of 8.00 rad/s in a 1.20 T field, starting with the normal of the plane of the coil perpendicular to the field. Assume that the positive max emf is reached first. (a) What (in V) is the peak emf? b) At what time is the peak emf first reached?
(c) At what time is the emf first at its most negative?
(d) What is the period of the AC voltage output?

in progress 0
3 years 2021-08-17T17:02:25+00:00 1 Answers 10 views 0

4.52389342117 V

0.196349540849 s

0.589048622548 s

0.785398163397 s

Explanation:

B = Magnetic field = 1.2 T

A = Area =

d = Diamter = 10 cm

N = Number of turns = 60 turn

= Angular velocity = 8 rad/s

Peak EMF is given by

Peak EMF is 4.52389342117 V

Time is given by (maximum)

Peak EMF is reached in 0.196349540849 s

Negative case

The time taken is 0.589048622548 s

For output voltage

Time taken is 0.785398163397 s