A 6.0-kg block initially at rest is pulled to the right along a frictionless, horizontal surface by a constant horizontal force of magnitude

Question

A 6.0-kg block initially at rest is pulled to the right along a frictionless, horizontal surface by a constant horizontal force of magnitude 12 N. Find the block’s speed after it is has moved through a horizontal distance of 3.0 m

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MichaelMet 7 hours 2021-07-22T01:19:24+00:00 1 Answers 0 views 0

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    2021-07-22T01:20:25+00:00

    Answer:

    Explanation:

    Given that,

    Block of mass M= 6kg

    Initially at rest u =0

    A force F = 12N is used in pulling it along the horizontal

    Distance moved s = 3m

    Speed.

    Using Newton second law

    ΣFx = ma

    12 = 6a

    Then, a = 12/6

    a = 2m/s²

    Then, using equation of motion

    v² = u² + 2as

    v² = 0² + 2×2×3

    v² = 0 + 12

    v = √ 12

    v = 3.46 m/s

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