A 57 kg ice skater moving to the right with a velocity of 1.2 m/s throws a 0.11 kg snowball to the right with a velocity of 31.5 m/s relativ

Question

A 57 kg ice skater moving to the right with a velocity of 1.2 m/s throws a 0.11 kg snowball to the right with a velocity of 31.5 m/s relative to the ground. What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice.

in progress 0
Helga 3 years 2021-07-31T20:22:24+00:00 1 Answers 6 views 0

Answers ( )

  1. binhan
    0
    2021-07-31T20:23:59+00:00
    Reply

    Answer:

     v_f = 1.14 m / s

    Explanation:

    This is an exercise of conservation of momentum, let’s define a system formed by the skater and the snowball, therefore the forces during the launch are internal and the moment is conserved.

    Initial instant. Before throwing the ball

            p₀ = M v₀

    Final moment. After throwing the snowball

           p_f = (M-m) v_f + m v

    the moment is preserved

            p₀ = p_f

            M v₀ = (M-m) v_f + m v

            v_f = \frac{M v_o - m v}{M-m}

    let’s calculate

           v_f = \frac{57 \ 1.2 - 0.11 \ 31.5}{ 57 - 0.11}

           v_f = 64.936 / 56.89

           v_f = 1.14 m / s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )