A 500-kg crate sits on a 10-degree ramp. If friction between the ramp and the crate is 800 N, what is the acceleration of the crate?

Question

A 500-kg crate sits on a 10-degree ramp. If friction between the ramp and the crate is 800 N, what is the acceleration of the crate?

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Ngọc Hoa 5 years 2021-07-22T08:10:25+00:00 1 Answers 18 views 0

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  1. thanhha
    0
    2021-07-22T08:11:37+00:00
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    By Newton’s second law, the net force acting on the crate parallel to the surface is

    ∑ F = mg sin(10°) – 800 N = ma

    where m = 500 kg is the mass of the crate and a is the acceleration.

    Solve for a :

    a = ((500 kg) (9.80 m/s^2) sin(10°) – 800 N) / (500 kg)

    a ≈ 0.102 m/s^2

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