A 50,000 kg train is rolling on its own down the track at 5 m/s. You grab the rope trailing behind it, and exert a stopping force of 2000 N.

Question

A 50,000 kg train is rolling on its own down the track at 5 m/s. You grab the rope trailing behind it, and exert a stopping force of 2000 N. How long does it take to stop the train?

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Diễm Kiều 5 years 2021-08-18T05:08:10+00:00 1 Answers 101 views 0

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  1. Neala
    0
    2021-08-18T05:09:42+00:00
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    Answer:

    t = 125 seconds

    Explanation:

    Given that,

    The mass of a train, m = 50,000 kg

    Initial speed, u = 5 m/s

    Stopping force, F = 2000 N

    We know that,

    Force, F = ma

    Where

    a is acceleration

    F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{50000(0-5)}{-2000}\\\\t=125\ s

    So, it will take 125 seconds to stop the car.

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