A 50.0 kg student climbs 5.00m up a rope at a constant speed. If the student’s power output is 200.0 W, how long does it take the student to

Question

A 50.0 kg student climbs 5.00m up a rope at a constant speed. If the student’s power output is 200.0 W, how long does it take the student to climb the rope ? How much work does the student do ?

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Farah 3 years 2021-08-05T06:59:13+00:00 1 Answers 1111 views 0

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    2021-08-05T07:00:29+00:00

    Answer:

    The time taken by the student to climb is 12.25 seconds and work done is 2450 J.            

    Explanation:

    Given that,

    Mass of the student, m = 50 kg

    The student climbs to a height of 5 meters at a constant speed.

    The student’s power output is 200.0 W, P = 200 W

    The power of an object is given by work done divided by time taken. So,

    P=\dfrac{W}{t}

    (b) W is work done,

    W=mgh\\\\W=50\times 9.8\times 5\\\\W=2450\ J

    (b)

    t=\dfrac{W}{P}\\\\t=\dfrac{2450}{200}\\\\t=12.25\ s

    So, the time taken by the student to climb is 12.25 seconds and work done is 2450 J.

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