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## A 3200-lb car is moving at 64 ft/s down a 30-degree grade when it runs out of fuel. Find its velocity after that if friction exerts a resist

Question

A 3200-lb car is moving at 64 ft/s down a 30-degree grade when it runs out of fuel. Find its velocity after that if friction exerts a resistive force with magnitude proportional to the square of the speed with k

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Physics
3 years
2021-08-09T15:28:48+00:00
2021-08-09T15:28:48+00:00 1 Answers
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## Answers ( )

Answer:The velocity is 40 ft/sec.

Explanation:Given that,Force = 3200 lb

Angle = 30°

Speed = 64 ft/s

The resistive force with magnitude proportional to the square of the speed,

Where, k = 1 lb s²/ft²

We need to calculate the velocityUsing balance equationPut the value into the formula

Put the value of k

At terminal velocity

So,

Hence, The velocity is 40 ft/sec.