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A 3200-lb car is moving at 64 ft/s down a 30-degree grade when it runs out of fuel. Find its velocity after that if friction exerts a resist
Question
A 3200-lb car is moving at 64 ft/s down a 30-degree grade when it runs out of fuel. Find its velocity after that if friction exerts a resistive force with magnitude proportional to the square of the speed with k
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Physics
3 years
2021-08-09T15:28:48+00:00
2021-08-09T15:28:48+00:00 1 Answers
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Answers ( )
Answer:
The velocity is 40 ft/sec.
Explanation:
Given that,
Force = 3200 lb
Angle = 30°
Speed = 64 ft/s
The resistive force with magnitude proportional to the square of the speed,
Where, k = 1 lb s²/ft²
We need to calculate the velocity
Using balance equation
Put the value into the formula
Put the value of k
At terminal velocity
So,
Hence, The velocity is 40 ft/sec.