A 31 kg child is traveling at 4 m/s while sledding down a hill. What is the child’s kinetic energy at the bottom of the hill?

Question

A 31 kg child is traveling at 4 m/s while sledding down a hill. What is the child’s kinetic energy at the bottom of the hill?

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Thạch Thảo 4 years 2021-08-22T00:06:29+00:00 1 Answers 8 views 0

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  1. Jezebel
    0
    2021-08-22T00:07:39+00:00
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    Answer:

    K.E = 248 J

    Explanation:

    Since the child is travelling at a given velocity. The kinetic energy of the child down the hill can be given by the following formula:

    K.E = \frac{1}{2}mv^2\\

    where,

    m = mass of the child = 31 kg

    v = velocity of the child = 4 m/s

    Therefore,

    K.E = \frac{1}{2}(31\ kg)(4\ m/s)^2\\

    K.E = 248 J

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