## A 30.0 kg cart travelling at 5.00 m/s collides with a 50.0 kg cart. Both carts immediately come to rest after the collision. What was the v

Question

A 30.0 kg cart travelling at 5.00 m/s collides with a 50.0 kg cart. Both carts immediately come to rest after the collision. What was the velocity of the 50.0 kg cart

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3 years 2021-08-30T16:49:11+00:00 1 Answers 7 views 0

30m/s

Explanation:

From the principle of conservation of momentum; it implies momentum before collision is same after collision hence

M1U1 +M2U2= M1V1 +M2V1

Since both objects comes to rest after collision it means the final velocity is 0 and this has been represented as V1; hence the right side of the equation evaluates to zero.

We can then rewrite the equation as;M1U1 +M2U2=0

Let U1 and U2 be the respective velocity for M1 =30kg and M2= 50kg respectively.

Hence the equation becomes on substituting M1,M2 and U1.

We have;

30×5 + 50×U2 = 0

150 +50U2=0

50U2 = -150

U2= -150/50 = -30m/s

Ignore the -ve sign which shows the direction of the 50kg mass was opposite that of 30kg