A 3.0 X 10^3 grams rock swings in a circle with a diameter of 1000 cm. Given the constant speed around the circle is 17.90 mph (a) what is t

Question

A 3.0 X 10^3 grams rock swings in a circle with a diameter of 1000 cm. Given the constant speed around the circle is 17.90 mph (a) what is the centripetal acceleration. *

in progress 0
Hải Đăng 5 months 2021-09-05T09:21:50+00:00 1 Answers 2 views 0

Answers ( )

  1. nguyetanh
    0
    2021-09-05T09:22:59+00:00
    Reply

    Answer:

    a = 12.8 m/s^2

    Explanation:

    To find the centripetal acceleration you use the following formula:

    a_c=\frac{v^2}{r}   (1)

    v: tangential speed of the rock = 17.90mph

    r: radius of the orbit = 1000cm/2 = 500cm = 0.5m

    You first change the units of the tangential velocity in order to replace the values of v and r in the equation (1):

    17.90mph*\frac{1609.34m}{1\ m}*\frac{1\ h}{3600\ s}=8m/s

    Then, you use the equation (1):

    a_c=\frac{(8m/s)^2}{5m}=12.8\frac{m}{s^2}

    hence, the centripetal acceleration is 12.8 m/s^2

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )