# A 200 kg golf cart strikes a 1500 kg car with 1000N of force, bringing its velocity from 5 m/s to 0 m/s in 1 second. How much force did the

Question

A 200 kg golf cart strikes a 1500 kg car with 1000N of force, bringing its velocity from 5 m/s to 0 m/s in 1 second. How much force did the car apply to the golf cart?

Question 6 options:

100 N

1000 N

1500 N

Not enough information has been given to solve the problem

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1 year 2021-09-05T14:51:25+00:00 2 Answers 6 views 0

The car applied a force of 1000 N to the golf cart

Explanation:

Based on the laws of conservation of linear momentum, we have that linear momentum is always conserved during a collision.

By Newtons Second law, (impulse law),

$$Ft = [m_{1}(v-u)+ m_{2}(v-u)]$$

Let m 1 be the mass of the golf cart, and v 1 its initial velocity. They are = 200 kg and 5 m/s respectively.

Let m 2 be the mass of the car, and  V 2 it initial velocity. They are = 1500 kg and 0 m/s respectively.

The time involved is 1 second

Applying the values of the variables to the formula, we have.

$$F \times 1 = [200 \times (5-0) – 1500 \times (0-0)]$$

From this we have that the force the car applied to the golf cart is = 1000 N