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# A 200 kg golf cart strikes a 1500 kg car with 1000N of force, bringing its velocity from 5 m/s to 0 m/s in 1 second. How much force did the

Question

A 200 kg golf cart strikes a 1500 kg car with 1000N of force, bringing its velocity from 5 m/s to 0 m/s in 1 second. How much force did the car apply to the golf cart?

Question 6 options:

100 N

1000 N

1500 N

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Physics
1 year
2021-09-05T14:51:25+00:00
2021-09-05T14:51:25+00:00 2 Answers
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## Answers ( )

Answer:The car applied a force of 1000 N to the golf cart

Explanation:Based on the laws of conservation of linear momentum, we have that linear momentum is always conserved during a collision.

By Newtons Second law, (impulse law),

[tex]Ft = [m_{1}(v-u)+ m_{2}(v-u)][/tex]

Let m 1 be the mass of the golf cart, and v 1 its initial velocity. They are = 200 kg and 5 m/s respectively.

Let m 2 be the mass of the car, and V 2 it initial velocity. They are = 1500 kg and 0 m/s respectively.

The time involved is 1 second

Applying the values of the variables to the formula, we have.

[tex]F \times 1 = [200 \times (5-0) – 1500 \times (0-0)][/tex]

From this we have that the force the car applied to the golf cart is = 1000 N

Answer:1000NExplanation:From Newton’s third law of motion, for every action there is an equal and opposite reaction. In other words, when two bodies are in collision, the forces acting between these bodies are equal in magnitude and opposite in direction.

In the case presented in the question, the bodies are the

and thegolf cartDuring collision, thecar.strikes the car with a 1000N of force (that is thegolf caraction). Consequential of this, though in the opposite direction, thewill apply an equal force of 1000N (that is thecarreaction) on thegolf car.Therefore the car applied a force of

1000Non the golf cart.