## A 20 kg block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 80 N to the left.

Question

A 20 kg block rests on a rough horizontal table. A rope is
attached to the block and is pulled with a force of 80 N to the
left. As a result, the block accelerates at 2.5 m/s2. The
coefficient of kinetic friction uk between the block and the table
is

in progress 0
3 years 2021-07-27T22:20:07+00:00 1 Answers 158 views 0

So we are applying 80 N on the block, 20kg in mass and it moves with the acceleration of 2.5 m/s/s

so we can find the force being applied on the block

F = ma

F = 20 X 2.5

F = 50 N

So only 50 N of the 80 N is being applied on the block.

Hence, the remaining 80-50 = 30 N force is being used to overcome friction

Force of Kinetic Friction = 30 N

Now, in this case the Normal Force will be equal to the Force applied by gravity(Mg)

So, Normal Force = 200 N

Coefficient of kinetic friction = Force of Kinetic Friction / Normal Force

Coefficient of kinetic friction = 30 / 200

Coefficient of Kinetic Friction = 0.15