A 20.0 mL solution of NaOH is neutralized with 24.1 mL of 0.200 M HBr. What is the concentration of the original NaOH solution

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A 20.0 mL solution of NaOH is neutralized with 24.1 mL of 0.200 M HBr. What is the concentration of the original NaOH solution

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Bơ 5 years 2021-07-13T03:49:14+00:00 1 Answers 27 views 0

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  1. Giakhanh
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    2021-07-13T03:50:18+00:00
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    Answer:

    0.241 M

    Explanation:

    We’ll begin by writing the balanced equation for the reaction. This is given below:

    HBr + NaOH —> NaBr + H₂O

    From the balanced equation above,

    The mole ratio of acid, HBr (nₐ) = 1

    The mole ratio of base, NaOH (n₆) = 1

    Finally, we shall determine the concentration of the NaOH solution. This can be obtained as follow:

    Volume of base, NaOH (V₆) = 20 mL

    Volume of acid, HBr (Vₐ) = 24.1 mL

    Concentration of acid, HBr (Cₐ) = 0.2 M

    Concentration of base, NaOH (C₆) =?

    CₐVₐ / C₆V₆ = nₐ/n₆

    0.2 × 24.1 / C₆ × 20 = 1/1

    4.82 / C₆ × 20 = 1

    Cross multiply

    C₆ × 20 = 4.82

    Divide both side by 20

    C₆ = 4.82 / 20

    C₆ = 0.241 M

    Therefore, the concentration of the NaOH solution is 0.241 M

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