A 2.25 Ω resistor, a 5.90 Ω resistor, and a 9.91 Ω resistor are connected in series with a 12.0 V battery. What is the equivalent resistance

Question

A 2.25 Ω resistor, a 5.90 Ω resistor, and a 9.91 Ω resistor are connected in series with a 12.0 V battery. What is the equivalent resistance? Submit Answer Tries 0/20 What is the current in each resistor?

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Calantha 6 months 2021-08-17T07:29:53+00:00 1 Answers 13 views 0

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    2021-08-17T07:31:19+00:00

    Answer:

    (a) The equivalent resistance is 18.06 Ω

    (b) The current in each resistor is 0.665 A

    Explanation:

    Given;

    first resistor, R₁ = 2.25 Ω

    second resistor, R₂ = 5.90 Ω

    third resistor, R₃ = 9.91 Ω

    Equivalent resistance;

    R_T = R_1 + R_2+ R_3\\\\

    R_T = 2.25 Ω +  5.90 Ω + 9.91 Ω

    R_T = 18.06 Ω

    The current in each resistor;

    For series connection, current is the same in every resistor.

    V = I(R₁ + R₂ + R₃)

    V = IR_T\\\\I = \frac{V}{R_T} \\\\I = \frac{12}{18.06} \\\\I = 0.665 \ A

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