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A 2.0-mm-long, 1.0-mmmm-diameter wire has a variable resistivity given by rho(x)=(2.5×10−6)[1+(x1.0m)2]Ωmrho(x)=(2.5×10−6)[1+(x1.0m)2]Ωm whe
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A 2.0-mm-long, 1.0-mmmm-diameter wire has a variable resistivity given by rho(x)=(2.5×10−6)[1+(x1.0m)2]Ωmrho(x)=(2.5×10−6)[1+(x1.0m)2]Ωm where xx is measured from one end of the wire.What is the current if this wire is connected to the terminals of a 17.0V battery?
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Physics
3 years
2021-07-25T12:59:44+00:00
2021-07-25T12:59:44+00:00 1 Answers
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Answer:
1.144 A
Explanation:
given that;
the length of the wire = 2.0 mm
the diameter of the wire = 1.0 mm
the variable resistivity R =
Voltage of the battery = 17.0 v
Now; the resistivity of the variable (dR) can be expressed as =
Taking the integral of both sides;we have:
R = 14.863 Ω
Since V = IR
I = 1.144 A
∴ the current if this wire if it is connected to the terminals of a 17.0V battery = 1.144 A