) A 1.0kW kettle contains 500g of boiling waterCalculate the time needed to evaporate all the water in the kettle (specific latent hea

Question

) A 1.0kW kettle contains 500g of boiling waterCalculate the time needed to evaporate all the water
in the kettle (specific latent heat of vaporization2.26 MJ kg​-1

in progress 0
Thu Nguyệt 5 years 2021-08-21T19:37:01+00:00 1 Answers 686 views 2

Answers ( )

  1. ThanhThu
    1
    2021-08-21T19:38:25+00:00
    Reply

    Answer:

    t = 1130 s = 18.83 min

    Explanation:

    First, we will calculate the energy required to evaporate 500 g of water:

    E = mL

    where,

    E = Energy Required for evaporation of water =?

    m = mass of water = 500 g = 0.5 kg

    L = Latent heat of vaporization of water = 2.26 MJ/kg = 2260 KJ/kg

    Therefore,

    E = (0.5\ kg)(2260\ KJ/kg)\\E = 1130\ KJ

    Now, we will calculate the time required:

    P = \frac{W}{t}\\\\t = \frac{W}{P}

    where,

    t = time = ?

    P = Power of kettle = 1 KW

    Therefore,

    t = \frac{1130\ KJ}{1 KW}\\\\

    t = 1130 s = 18.83 min

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )