A 0.83 kg spike is hammered into a railroad tie. The initial speed of the spike is equal to 3.8 m/s. If the tie and spike together absorb 89

Question

A 0.83 kg spike is hammered into a railroad tie. The initial speed of the spike is equal to 3.8 m/s. If the tie and spike together absorb 89.4 percent of the spike’s initial kinetic energy as internal energy, calculate the increase in internal energy of the tie and spike. Answer in units of J.

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Hải Đăng 3 years 2021-08-06T04:52:14+00:00 1 Answers 10 views 0

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  1. linhdan
    0
    2021-08-06T04:54:13+00:00
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    Answer:

    U = 5.36 J

    Explanation:

    Given,

    mass of the spike = 0.83 Kg

    initial speed of the spike = 3.8 m/s

    energy absorbed = 89.4 %

    Change in internal energy = ?

    Kinetic energy absorbed by the spike is converted into internal energy.

    \Delta KE = internal\ energy(U)

    U = 89.4 \% \times \dfrac{1}{2}mv^2

    U = 0.894\times \dfrac{1}{2}\times 0.83\times 3.8^2

    U = 5.36 J

    Hence, increase in internal energy is equal to 5.36 J.

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