A 0.50 kg object is at rest. A 2.88 N force to the right acts on the object during a time interval of 1.48 s. a) What is the velocity of the

Question

A 0.50 kg object is at rest. A 2.88 N force to the right acts on the object during a time interval of 1.48 s. a) What is the velocity of the object at the end of this time interval? Answer in units of m/s.

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Thiên Di 3 years 2021-09-04T13:59:34+00:00 1 Answers 7 views 0

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  1. Acacia
    0
    2021-09-04T14:00:44+00:00
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    Answer:

    8.5m/s

    Explanation:

    We are given that

    Mass of object=m=0.50 kg

    Initial velocity, u=0

    Force=F=2.88 N

    Time=1.48 s

    a.We know that

    F=ma

    Using the formula

    2.88=0.50a

    a=\frac{2.88}{0.50}=5.76m/s^2

    a=\frac{v-u}{t}

    Using the formula

    5.76=\frac{v-0}{1.48}

    v=5.76\times 1.48=8.5m/s

    Hence, the velocity of the object at the end of this time interval=8.5m/s

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