A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on its surface. W

Question

A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on its surface. What is the potential (in V) near its surface?

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Jezebel 4 years 2021-08-31T10:10:21+00:00 1 Answers 4 views 0

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  1. Farah
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    2021-08-31T10:11:57+00:00
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    Answer:

    Therefore,

    The potential (in V) near its surface is 186.13 Volt.

    Explanation:

    Given:

    Diameter of sphere,

    d= 0.29 cm

    radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm

    r = 0.145\ cm = 0.145\times 10^{-2}\ m

    Charge ,

    Q = 30.0\ pC=30\times 10^{-12}

    To Find:

    Electric potential , V = ?

    Solution:

    Electric Potential at point surface is given as,

    V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}

    Where,  

    V= Electric potential,  

    ε0 = permeability free space = 8.85 × 10–12 F/m

    Q = Charge  

    r = Radius  

    Substituting the values we get

    V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}

    V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt

    Therefore,

    The potential (in V) near its surface is 186.13 Volt.

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