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## A 0.2 kg baseball moving with a velocity of 20 m/s is struck by a bat. The baseball reverses its direction and moves with a velocity of 40 m

Question

A 0.2 kg baseball moving with a velocity of 20 m/s is struck by a bat. The baseball reverses its direction and moves with a velocity of 40 m/s . What is the average force exerted on the ball if the bat is in contact with the ball for 0.006 ?

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Physics
3 years
2021-08-12T13:41:22+00:00
2021-08-12T13:41:22+00:00 1 Answers
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## Answers ( )

Average force is 666.67 NExplanation:Given that :m = Mass of the baseball = 0.2 kg

u = Initial velocity = 20 m/s

v = Final velocity = 40 m/s

t = Time taken for change in velocity = 0.006 s

We know:

Force exerted = mass × acceleration = m ×aAcceleration can be found by means of dividing the change in velocity measured in m/s by the time taken in seconds.a ==m/s²Now we have to find the force using the formula, F = mass × acceleration as,F = 0.2 kg ×3333.3 ms⁻² = 666.67 N