“A 0.15 kg ball moving at 40 m/s is struck by a bat. The bat reverses the ball’s direction and gives it a speed of 50 m/s. What average forc

Question

“A 0.15 kg ball moving at 40 m/s is struck by a bat. The bat reverses the ball’s direction and gives it a speed of 50 m/s. What average force does the bat apply to the ball if they are in contact for 6.0 ×10 -3 s?”

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Mít Mít 6 months 2021-09-04T20:20:09+00:00 1 Answers 0 views 0

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    2021-09-04T20:21:15+00:00

    Answer:

    -2250 N

    Explanation:

    From the question,

    Using.

    F = m(v-u)/t ……………… Equation 1

    Where F = Average force the bat apply to the ball, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time.

    Given: m = 0.15 kg, v = -50 m/s(reversed direction), u = 40 m/s, t = 6.0×10⁻³ s = 0.006 s.

    Substitute into equation 1

    F = 0.15(-50-40)/0.006

    F = 0.15(-90)/0.006

    F = -2250 N.

    The force is negative because it opposes the initial motion of the ball.

    Hence the bat average force = -2250 N

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