A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When released the s

Question

A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When released the spring toy pops up and reaches a maximum height of 1.5 meters.

1) How much elastic potential energy is initially stored in the spring?

2)How much internal energy is produced as the toy springs up to its maximum height?

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Nho 5 months 2021-09-03T21:37:18+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-09-03T21:39:14+00:00

    Answer:

    (1) V = 0.2 J (2) 0.05J

    Explanation:

    Solution

    Given that:

    K = 160 N/m

    x = 0.05 m

    Now,

    (1) we solve for the  initial potential energy stored

    Thus,

    V = 1/2 kx² = 0.5 * 160 * (0.05)²

    Therefore V = 0.2 J

    (2)Now, we solve for how much of the internal energy is produced as the toy springs up to its maximum height.

    By using the energy conversion, we have the following

    ΔV = mgh

    =(0.1/9.8) * 9.8 * 1.5 = 0.15J

    The internal energy = 0.2 -0.15

    =0.05J

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