A 0.10-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the object is trav

Question

A 0.10-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the object is traveling to the left at 3.0 m/s. What is the magnitude of the impulse (in N-s) acting on the object? The answer must be positive. (NEVER include units in the answer to a numerical question.)

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Thu Thủy 4 years 2021-08-18T11:21:12+00:00 1 Answers 39 views 0

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  1. haidang
    0
    2021-08-18T11:23:11+00:00
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    Answer:

    Explanation:

    Impulse = change in momentum

    = m v – mu , ( u is initial velocity and v is final )

    0.1 [ 3 – ( – 3) ]

    = 0.6

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