A 0.10-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the object is traveling to the left at 3.0 m/s. What is the magnitude of the impulse (in N-s) acting on the object? The answer must be positive. (NEVER include units in the answer to a numerical question.)

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Answer:Explanation:Impulse = change in momentum

= m v – mu , ( u is initial velocity and v is final )

0.1 [ 3 – ( – 3) ]

= 0.6