7. Imagine you are pushing a 15 kg cart full of 25 kg of bottled water up a 10o ramp. If the coefficient of friction is 0.02, what is the fr

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7. Imagine you are pushing a 15 kg cart full of 25 kg of bottled water up a 10o ramp. If the coefficient of friction is 0.02, what is the friction force you must overcome to push the cart up the ramp

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Thạch Thảo 3 years 2021-08-25T09:08:56+00:00 1 Answers 24 views 0

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    2021-08-25T09:10:26+00:00

    Answer:

    The frictional force needed to overcome the cart is 4.83N

    Explanation:

    The frictional force can be obtained using the following formula:

    F= \mu R

    where \mu is the coefficient of friction = 0.02

    R = Normal reaction of the load = mgcos\theta = 25 \times 9.81 \times cos 10 = 241.52N

    Now that we have the necessary parameters that we can place into the equation, we can now go ahead and make our substitutions, to get the value of F.

    F=0.02 \times 241.52N

    F = 4.83 N

    Hence, the frictional force needed to overcome the cart is 4.83N

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