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– 6 + \sqrt{9 – 8a} = 1−6+ 9−8a =1
Question
– 6 + \sqrt{9 – 8a} = 1−6+
9−8a
=1
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Mathematics
1 year
2021-09-04T05:50:08+00:00
2021-09-04T05:50:08+00:00 1 Answers
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Answers ( )
Answer:
[tex]a = -5[/tex]
Step-by-step explanation:
Given
[tex]- 6 + \sqrt{9 – 8a} = 1[/tex]
Required
Solve for a
[tex]- 6 + \sqrt{9 – 8a} = 1[/tex]
Add 6 to both sides
[tex]6- 6 + \sqrt{9 – 8a} = 1+6[/tex]
[tex]\sqrt{9 – 8a} = 7[/tex]
Square both sides
[tex]( \sqrt{9 – 8a})^2 = 7^2[/tex]
[tex]9 – 8a = 49[/tex]
Subtract 9 from both sides
[tex]9-9 – 8a = 49-9[/tex]
[tex]- 8a = 40[/tex]
Make a the subject
[tex]a = -\frac{40}{8}[/tex]
[tex]a = -5[/tex]