– 6 + \sqrt{9 – 8a} = 1−6+ 9−8a ​ =1​

Question

– 6 + \sqrt{9 – 8a} = 1−6+
9−8a
​
=1​

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Minh Khuê 1 year 2021-09-04T05:50:08+00:00 1 Answers 0 views 0

Answers ( )

  1. thienthi
    0
    2021-09-04T05:51:12+00:00
    Reply

    Answer:

    [tex]a = -5[/tex]

    Step-by-step explanation:

    Given

    [tex]- 6 + \sqrt{9 – 8a} = 1[/tex]

    Required

    Solve for a

    [tex]- 6 + \sqrt{9 – 8a} = 1[/tex]

    Add 6 to both sides

    [tex]6- 6 + \sqrt{9 – 8a} = 1+6[/tex]

    [tex]\sqrt{9 – 8a} = 7[/tex]

    Square both sides

    [tex]( \sqrt{9 – 8a})^2 = 7^2[/tex]

    [tex]9 – 8a = 49[/tex]

    Subtract 9 from both sides

    [tex]9-9 – 8a = 49-9[/tex]

    [tex]- 8a = 40[/tex]

    Make a the subject

    [tex]a = -\frac{40}{8}[/tex]

    [tex]a = -5[/tex]

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