5. Mr. Robson bought bags of orange for =N=2,500 each. He sold them for=N=90,000 at a loss of How many bags of orange did he buy?<

Question

5.
Mr. Robson bought bags of orange for =N=2,500 each. He sold them for=N=90,000 at a loss of
How many bags of orange did he buy?
20%
(A) 60
(B)
80
(C) 50
(DY 45
The
CAL​

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Linh Đan 6 months 2021-09-04T19:51:28+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-09-04T19:53:14+00:00

    Answer:

    45

    Step-by-step explanation:

    Let us assume the Bags of oranges be x

    Now the cost price is 2500x

    Sale price N = 90,000

    Loss =20%

    As we know that

    Cost price= selling price × 100/ 100-percentage loss

    = 90,000 ×  100/ 100- 20

    = 90,000 ×  100 /80

    Cost price= 112,500

    Now

    The Number of bags of oranges is

    = 112,500 ÷ 2500

    = 45

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