4. Water stands 12.0 m deep in a storage tank whose top is open to the atmosphere at 1.00 atm. The density of water is given as 1000 kg

Question

4. Water stands 12.0 m deep in a storage tank whose top is open to the atmosphere at
1.00 atm. The density of water is given as 1000 kg/m² and some pressure conversion
are 1 Pa = 1 N/m² while 1 atm = 101 325 Pa.
a) What is the absolute pressure at the bottom of the tank?
b) What is the gauge pressure at the bottom of the tank?
[4]
[4]​

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Huyền Thanh 5 years 2021-07-19T13:39:27+00:00 1 Answers 600 views 0

Answers ( )

  1. Edana
    0
    2021-07-19T13:40:36+00:00
    Reply

    Answer:

    P=217600Pa

    Explanation:

    From the question we are told that:

    Density \rho=1000kg/m^3

    Depth of Water d=12.0m

    Generally the equation for Pressure is mathematically given by

     P=\rho gh

     P=1000*9.8*12

     P=117600N/m^2

    Therefore

    Absolute Pressure=P+P’

    Where

    P=Pressure under water

    P’=Atmospheric Pressure

    Therefore

     P_A=P+P'

     P_A=117,600+10^5

     P=217600Pa

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