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3 years ago, Nancy’s age was more than Khaled’s age by 2, 4 years from now, twice Nancy’s age will be more than Khaled’s age by 16. Find the
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3 years ago, Nancy’s age was more than Khaled’s age by 2, 4 years from now, twice Nancy’s age will be more than Khaled’s age by 16. Find their ages.
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Mathematics
5 years
2021-08-22T03:50:37+00:00
2021-08-22T03:50:37+00:00 1 Answers
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Answer:
Nancy’s age is 11years and Khaled’s age is 10years
Step-by-step explanation:
Let Nancy’s present age be x
Let Khaled’s present age b y
3 years ago
Nancy = x – 3
Khaled = y – 3
If 3 years ago, Nancy’s age was more than Khaled’s age by 2, then;
x-3 = y-3 + 2
x – 3 = y – 1
x- y = -1+3
x – y = 2 …1
4 years from now,
Nancy = x+4
Khaled = y+4
If by 4years from now, twice Nancy’s age will be more than Khaled’s age by 16, then;
2(x+4) = y+4 + 16
2x+8 = y+20
2x-y = 20-8
2x-y = 12 ….2
Subtract 1 from 2;
x – 2x = 1 – 12
-x = -11
x = 11
Since x – y = 1
11 – y = 1
y = 11-1
y = 10
Hence Nancy’s age is 11years and Khaled’s age is 10years